What are the solutions to the equation 400=16(t)^2 ?

The solutions to the equation 400=16(t)^2 are t=5,t=-5

Find the zeros of 400=16(t)^2

The zeros of 400=16(t)^2 are t=5,t=-5

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400 = 16 (t)^{2}

t = 5, t = - 5

Solution steps

400 = 16 t^{2}

Switch sides

16 t^{2} = 400

Divide both sides by

16

t^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 25, t = - 25

25 = 5

- 25 = - 5

t = 5, t = - 5

\frac{3}{4} = \frac{1}{2} + \frac{d}{3}

4 x (x + 14) = 14

\frac{1}{1 0 ^{- 1}}

\frac{12 n ^{3}}{3 ( n ^{4} ) ^{2}}

15 > 2 x - 7

What are the solutions to the equation 400=16(t)^2 ?
The solutions to the equation 400=16(t)^2 are t=5,t=-5
Find the zeros of 400=16(t)^2
The zeros of 400=16(t)^2 are t=5,t=-5