What is the answer to solvefor x,3z-2=2x+3y ?

The answer to solvefor x,3z-2=2x+3y is x=(3z-2-3y)/2

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solvefor x,3z-2=2x+3y

solve for

x, 3 z - 2 = 2 x + 3 y

x = \frac{3 z - 2 - 3 y}{2}

Solution steps

3 z - 2 = 2 x + 3 y

Switch sides

2 x + 3 y = 3 z - 2

Move

3 y

to the right side

2 x = 3 z - 2 - 3 y

Divide both sides by

2

x = \frac{3 z - 2 - 3 y}{2}

- 37 - 7 r = - 3 (5 r - 9)

y, x = \frac{4 y}{3}

3 x - 5 = x + 5

8 a = 5

2 (3 - x) = 3 (x - 4) + 15

What is the answer to solvefor x,3z-2=2x+3y ?
The answer to solvefor x,3z-2=2x+3y is x=(3z-2-3y)/2