What is the answer to (x-1)/7+(2-x}{14}=2-\frac{x+2)/4 ?

The answer to (x-1)/7+(2-x}{14}=2-\frac{x+2)/4 is x= 14/3

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(x-1)/7+(2-x}{14}=2-\frac{x+2)/4

\frac{x - 1}{7} + \frac{2 - x}{14} = 2 - \frac{x + 2}{4}

x = \frac{14}{3}

Decimal Notation

x = 4.66666 \dots

Solution steps

\frac{x - 1}{7} + \frac{2 - x}{14} = 2 - \frac{x + 2}{4}

Multiply by LCM

4 (x - 1) + 2 (- x + 2) = 56 - 7 (x + 2)

Expand

4 (x - 1) + 2 (- x + 2) : 2 x

Expand

56 - 7 (x + 2) : - 7 x + 42

2 x = - 7 x + 42

Move

7 x

to the left side

9 x = 42

Divide both sides by

9

x = \frac{14}{3}

8 x = 5

\frac{n}{4} = 13

- t + 10 = t + 4

75 + 50 x = 25 + 70 x

x, x + 6 y = 0

What is the answer to (x-1)/7+(2-x}{14}=2-\frac{x+2)/4 ?
The answer to (x-1)/7+(2-x}{14}=2-\frac{x+2)/4 is x= 14/3
Solve for x: (x-1)/7+(2-x}{14}=2-\frac{x+2)/4
The solution is x= 14/3