What is (4+i)/(-3-2i) ?

The solution to (4+i)/(-3-2i) is -14/13+5/13 i

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simplify (4+i)/(-3-2i)

simplify

\frac{4 + i}{- 3 - 2 i}

- \frac{14}{13} + \frac{5}{13} i

Solution steps

\frac{4 + i}{- 3 - 2 i}

Multiply by the conjugate

\frac{- 3 + 2 i}{- 3 + 2 i}

= \frac{( 4 + i ) ( - 3 + 2 i )}{( - 3 - 2 i ) ( - 3 + 2 i )}

Simplify

\frac{( 4 + i ) ( - 3 + 2 i )}{( - 3 - 2 i ) ( - 3 + 2 i )} : \frac{- 14 + 5 i}{13}

= \frac{- 14 + 5 i}{13}

Rewrite in standard complex form:

- \frac{14}{13} + \frac{5}{13} i

= - \frac{14}{13} + \frac{5}{13} i

x^{2} - 16 > (x + 4) (x^{2} - 3 x - 1)

4 b (5 b - 3) - 2 (b^{2} - 7 b - 4)

n + 5 > - 3

216 x^{3} + 125 y^{3}

\frac{2 x - 1}{x + 1} = 3