What is 2x^2+4x+3>= x^2-2x-5 ?

The solution to 2x^2+4x+3>= x^2-2x-5 is x =-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2+4x+3>= x^2-2x-5

2 x^{2} + 4 x + 3 \geq x^{2} - 2 x - 5

x \leq - 4 or x \geq - 2

Interval Notation

(- \infty, - 4] \cup [- 2, \infty)

Solution steps

2 x^{2} + 4 x + 3 \geq x^{2} - 2 x - 5

Rewrite in standard form

x^{2} + 6 x + 8 \geq 0

Factor

x^{2} + 6 x + 8 : (x + 2) (x + 4)

(x + 2) (x + 4) \geq 0

Identify the intervals

x \leq - 4 or x \geq - 2

(\frac{1}{4 x ^{\frac{2}{3}}})^{2}

- x^{3} + 27 x - 54

\frac{4}{a + 1} + \frac{3}{a + 2}

x^{3} + 2 x^{2} - 8 x

What is 2x^2+4x+3>= x^2-2x-5 ?
The solution to 2x^2+4x+3>= x^2-2x-5 is x<=-4\lor x>=-2