What is the answer to solvefor f,f=(2x)/(sqrt(9-x^2-y^2)) ?

The answer to solvefor f,f=(2x)/(sqrt(9-x^2-y^2)) is f=(2x)/(sqrt(9-x^2-y^2))

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solvefor f,f=(2x)/(sqrt(9-x^2-y^2))

solve for

f, f = \frac{2 x}{9 - x ^{2} - y ^{2}}

f = \frac{2 x}{9 - x ^{2} - y ^{2}}

Solution steps

f = \frac{2 x}{9 - x ^{2} - y ^{2}}

Could not simplify further

f = \frac{2 x}{9 - x ^{2} - y ^{2}}

10 p - 40 = 310

1 0^{0.5} = 3.16

0.4 (x + 5) = 0.1 (4 x + 2)

4 = \frac{5}{3} y

4 x - 4 = 32

What is the answer to solvefor f,f=(2x)/(sqrt(9-x^2-y^2)) ?
The answer to solvefor f,f=(2x)/(sqrt(9-x^2-y^2)) is f=(2x)/(sqrt(9-x^2-y^2))