What is the answer to solvefor X,Y=X5+3X-2+4X ?

The answer to solvefor X,Y=X5+3X-2+4X is X=(Y+2)/(12)

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solvefor X,Y=X5+3X-2+4X

solve for

X, Y = X 5 + 3 X - 2 + 4 X

X = \frac{Y + 2}{12}

Solution steps

Y = X \cdot 5 + 3 X - 2 + 4 X

Switch sides

X \cdot 5 + 3 X - 2 + 4 X = Y

Group like terms

5 X + 3 X + 4 X - 2 = Y

Add similar elements:

5 X + 3 X + 4 X = 12 X

12 X - 2 = Y

Move

2

to the right side

12 X = Y + 2

Divide both sides by

12

X = \frac{Y + 2}{12}

- (5 x - 4) = - 5 x + 5

5 a = 2 a + 15

\frac{3}{4} = \frac{x}{4}

8 (y + 1) = 88

x, ∣ y ∣ = 2 x + 4

What is the answer to solvefor X,Y=X5+3X-2+4X ?
The answer to solvefor X,Y=X5+3X-2+4X is X=(Y+2)/(12)