What is the answer to ln(400)-ln(1000-400)=t+ln(1/9) ?

The answer to ln(400)-ln(1000-400)=t+ln(1/9) is t=ln(6)

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ln(400)-ln(1000-400)=t+ln(1/9)

ln (400) - ln (1000 - 400) = t + ln (\frac{1}{9})

t = ln (6)

Decimal Notation

t = 1.79175 \dots

Solution steps

ln (400) - ln (1000 - 400) = t + ln (\frac{1}{9})

Switch sides

t + ln (\frac{1}{9}) = ln (400) - ln (1000 - 400)

Subtract the numbers:

1000 - 400 = 600

t + ln (\frac{1}{9}) = ln (400) - ln (600)

Move

ln (\frac{1}{9})

to the right side

t = ln (6)

7 x + 10 = 9 x - 2

11 m - 8 - 6 m = 22

(5 x - 23) + (7 x - 1) = 180

x, f = 2 x yz

x, - 3 x + y = 11

What is the answer to ln(400)-ln(1000-400)=t+ln(1/9) ?
The answer to ln(400)-ln(1000-400)=t+ln(1/9) is t=ln(6)
Solve for t: ln(400)-ln(1000-400)=t+ln(1/9)
The solution is t=ln(6)