What is (m^{(-5)/2})/(m^{-2)} ?

The solution to (m^{(-5)/2})/(m^{-2)} is 1/(m^{1/2)}

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simplify (m^{(-5)/2})/(m^{-2)}

simplify

\frac{m ^{\frac{- 5}{2}}}{m ^{- 2}}

\frac{1}{m ^{\frac{1}{2}}}

Solution steps

\frac{m ^{\frac{- 5}{2}}}{m ^{- 2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

= m^{\frac{- 5}{2} - (- 2)}

Apply rule

- (- a) = a

= m^{\frac{- 5}{2} + 2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= m^{- \frac{5}{2} + 2}

Join

- \frac{5}{2} + 2 : - \frac{1}{2}

= m^{- \frac{1}{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{m ^{\frac{1}{2}}}

x^{2} - 6 x y + 9 y^{2}

- 4 x - 1 = - 3 x + 5

10 + x \leq - 10

x^{2} + 15 x + 44 \geq 0

v - \frac{5}{8} = - \frac{1}{4}

What is (m^{(-5)/2})/(m^{-2)} ?
The solution to (m^{(-5)/2})/(m^{-2)} is 1/(m^{1/2)}