What is the answer to solvefor b,g(b+c)=-3x+1 ?

The answer to solvefor b,g(b+c)=-3x+1 is b=(-3x+1)/g-c;\quad g\ne 0

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solvefor b,g(b+c)=-3x+1

solve for

b, g (b + c) = - 3 x + 1

b = \frac{- 3 x + 1}{g} - c; g \neq = 0

Solution steps

g (b + c) = - 3 x + 1

Divide both sides by

g; g \neq = 0

b + c = \frac{- 3 x + 1}{g}; g \neq = 0

Move

c

to the right side

b = \frac{- 3 x + 1}{g} - c; g \neq = 0

a, ab = c d

x, (m + 3) x + (n - 2) y = 14

x, 1 x + 1 y = 10

a (x - 2) + b (x - 4) = x + 2

5 (1 - 2 (2 + x)) = 4 x

What is the answer to solvefor b,g(b+c)=-3x+1 ?
The answer to solvefor b,g(b+c)=-3x+1 is b=(-3x+1)/g-c;\quad g\ne 0