What is the answer to |x^2+2x|=1 ?

The answer to |x^2+2x|=1 is x=-1-sqrt(2)\lor x=-1\lor x=-1+sqrt(2)

Solve for x: |x^2+2x|=1

The solution is x=-1-sqrt(2)\lor x=-1\lor x=-1+sqrt(2)

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x^{2} + 2 x = 1

x = - 1 - 2 or x = - 1 or x = - 1 + 2

Decimal Notation

x = - 2.41421 \dots, x = - 1, x = 0.41421 \dots

Solution steps

x^{2} + 2 x = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 2 x = - 1 or x^{2} + 2 x = 1

x^{2} + 2 x = - 1 or x^{2} + 2 x = 1

x = - 1 or (x = - 1 - 2 or x = - 1 + 2)

x = - 1 - 2 or x = - 1 or x = - 1 + 2

3 n^{2} - 8 n - 3

81 a^{4} - 49 b^{2}

x^{2} - 10 x + 100 = 0

\frac{5}{X - 1} < 3

x^{\frac{3}{4}} x^{\frac{5}{4}}

What is the answer to |x^2+2x|=1 ?
The answer to |x^2+2x|=1 is x=-1-sqrt(2)\lor x=-1\lor x=-1+sqrt(2)
Solve for x: |x^2+2x|=1
The solution is x=-1-sqrt(2)\lor x=-1\lor x=-1+sqrt(2)