What is the answer to solvefor y,xy+x+y=2020 ?

The answer to solvefor y,xy+x+y=2020 is y=(2020-x)/(x+1);\quad x\ne-1

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solvefor y,xy+x+y=2020

solve for

y, x y + x + y = 2020

y = \frac{2020 - x}{x + 1}; x \neq = - 1

Solution steps

x y + x + y = 2020

Move

x

to the right side

x y + y = 2020 - x

Factor

x y + y : y (x + 1)

y (x + 1) = 2020 - x

Divide both sides by

x + 1; x \neq = - 1

y = \frac{2020 - x}{x + 1}; x \neq = - 1

2 x + 2 - 3 x + 6 = x - 6

\frac{3 x}{2} = - \frac{12}{7}

- 4 = \frac{k + 3}{2}

- \frac{j}{3} - 2 = 0

7 x + 3 x - 18 = 6 (x + 3)

What is the answer to solvefor y,xy+x+y=2020 ?
The answer to solvefor y,xy+x+y=2020 is y=(2020-x)/(x+1);\quad x\ne-1