What is the answer to 4x(x-2)=(2x+1)(2x-3) ?

The answer to 4x(x-2)=(2x+1)(2x-3) is x= 3/4

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4x(x-2)=(2x+1)(2x-3)

4 x (x - 2) = (2 x + 1) (2 x - 3)

x = \frac{3}{4}

Decimal Notation

x = 0.75

Solution steps

4 x (x - 2) = (2 x + 1) (2 x - 3)

Expand

4 x (x - 2) : 4 x^{2} - 8 x

Expand

(2 x + 1) (2 x - 3) : 4 x^{2} - 4 x - 3

4 x^{2} - 8 x = 4 x^{2} - 4 x - 3

Subtract

4 x^{2} - 4 x

from both sides

4 x^{2} - 8 x - (4 x^{2} - 4 x) = 4 x^{2} - 4 x - 3 - (4 x^{2} - 4 x)

Simplify

- 4 x = - 3

Divide both sides by

- 4

x = \frac{3}{4}

(- 1) - 4

2 x < 17

\frac{y}{3} = 12

(x + 4) (x + 1) = 0

5^{3}

What is the answer to 4x(x-2)=(2x+1)(2x-3) ?
The answer to 4x(x-2)=(2x+1)(2x-3) is x= 3/4
Solve for x: 4x(x-2)=(2x+1)(2x-3)
The solution is x= 3/4