What is the answer to (c-4)(c+2)=c^2+2c-8 ?

The answer to (c-4)(c+2)=c^2+2c-8 is c=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(c-4)(c+2)=c^2+2c-8

(c - 4) (c + 2) = c^{2} + 2 c - 8

c = 0

Solution steps

(c - 4) (c + 2) = c^{2} + 2 c - 8

Expand

(c - 4) (c + 2) : c^{2} - 2 c - 8

c^{2} - 2 c - 8 = c^{2} + 2 c - 8

Move

8

to the right side

c^{2} - 2 c = c^{2} + 2 c

Subtract

c^{2} + 2 c

from both sides

c^{2} - 2 c - (c^{2} + 2 c) = c^{2} + 2 c - (c^{2} + 2 c)

Simplify

- 4 c = 0

Divide both sides by

- 4

c = 0

a, 3 a b^{3} + a b^{3} = x a b^{y}

\frac{x + 16}{3} + 5 = 3

x, 20% x + 35% y = 25 (26%)

5 x + 3 x - 4 = 5 + 7 x

x, 2 x = y + 2

What is the answer to (c-4)(c+2)=c^2+2c-8 ?
The answer to (c-4)(c+2)=c^2+2c-8 is c=0
Solve for c: (c-4)(c+2)=c^2+2c-8
The solution is c=0