What is the answer to (x+1)^2-(x-1)^2+12=0 ?

The answer to (x+1)^2-(x-1)^2+12=0 is x=-3

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(x+1)^2-(x-1)^2+12=0

(x + 1)^{2} - (x - 1)^{2} + 12 = 0

x = - 3

Solution steps

(x + 1)^{2} - (x - 1)^{2} + 12 = 0

Move

12

to the right side

(x + 1)^{2} - (x - 1)^{2} = - 12

Expand

(x + 1)^{2} - (x - 1)^{2} : 4 x

4 x = - 12

Divide both sides by

4

x = - 3

2 + 2 x + 1 = 0

3 (a - 5) + 6 (a - 2) = 9

5 x + 8 = 3 x

3 x - \frac{x}{8} = 23

6.2 + x = 19.8

What is the answer to (x+1)^2-(x-1)^2+12=0 ?
The answer to (x+1)^2-(x-1)^2+12=0 is x=-3
Solve for x: (x+1)^2-(x-1)^2+12=0
The solution is x=-3