What is the answer to 15=a_{0}(s+3)+a_{1}s ?

The answer to 15=a_{0}(s+3)+a_{1}s is s=(15-3a_{0})/(a_{0)+a_{1}};\quad a_{0}\ne-a_{1}

Solve for s: 15=a_{0}(s+3)+a_{1}s

The solution is s=(15-3a_{0})/(a_{0)+a_{1}};\quad a_{0}\ne-a_{1}

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15 = a_{0} (s + 3) + a_{1} s

s = \frac{15 - 3 a _{0}}{a _{0} + a _{1}}; a_{0} \neq = - a_{1}

Solution steps

15 = a_{0} (s + 3) + a_{1} s

Switch sides

a_{0} (s + 3) + a_{1} s = 15

Expand

a_{0} (s + 3) : a_{0} s + 3 a_{0}

a_{0} s + 3 a_{0} + a_{1} s = 15

Move

3 a_{0}

to the right side

a_{0} s + a_{1} s = 15 - 3 a_{0}

Factor

a_{0} s + a_{1} s : s (a_{0} + a_{1})

s (a_{0} + a_{1}) = 15 - 3 a_{0}

Divide both sides by

a_{0} + a_{1}; a_{0} \neq = - a_{1}

s = \frac{15 - 3 a _{0}}{a _{0} + a _{1}}; a_{0} \neq = - a_{1}

7 x = 3 x + 20

\frac{2 x - 1}{5} - \frac{x}{6} = \frac{8 - 3 x}{10}

\frac{x}{5} - \frac{2}{3} + x = 0

y, 8 + 3 y = 1 + 9 x

\frac{x}{4} + \frac{x}{3} = x - 100

What is the answer to 15=a_{0}(s+3)+a_{1}s ?
The answer to 15=a_{0}(s+3)+a_{1}s is s=(15-3a_{0})/(a_{0)+a_{1}};\quad a_{0}\ne-a_{1}
Solve for s: 15=a_{0}(s+3)+a_{1}s
The solution is s=(15-3a_{0})/(a_{0)+a_{1}};\quad a_{0}\ne-a_{1}