What is the answer to 2pi(1+3sqrt(2))=pi((sqrt(2)+y)^2-y^2) ?

The answer to 2pi(1+3sqrt(2))=pi((sqrt(2)+y)^2-y^2) is y=3

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2pi(1+3sqrt(2))=pi((sqrt(2)+y)^2-y^2)

2 π (1 + 32) = π ((2 + y)^{2} - y^{2})

y = 3

Solution steps

2 π (1 + 32) = π ((2 + y)^{2} - y^{2})

Switch sides

π ((2 + y)^{2} - y^{2}) = 2 π (1 + 32)

Divide both sides by

π

22 y + 2 = 2 (1 + 32)

Move

2

to the right side

22 y = 62

Divide both sides by

22

y = 3

x, 6 x + 8 y = 10

x, 6 x + 8 y = 40

2 x - [7 - x + (x - 2)] = 3

\frac{x}{6} = \frac{15}{40}

x, 2 (x - 1) + \frac{y}{2} + 4 = 0

What is the answer to 2pi(1+3sqrt(2))=pi((sqrt(2)+y)^2-y^2) ?
The answer to 2pi(1+3sqrt(2))=pi((sqrt(2)+y)^2-y^2) is y=3