What are the solutions to the equation 6x+9=x^2 ?

The solutions to the equation 6x+9=x^2 are x=3(1+sqrt(2)),x=3(1-sqrt(2))

Find the zeros of 6x+9=x^2

The zeros of 6x+9=x^2 are x=3(1+sqrt(2)),x=3(1-sqrt(2))

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6 x + 9 = x^{2}

x = 3 (1 + 2), x = 3 (1 - 2)

Decimal Notation

x = 7.24264 \dots, x = - 1.24264 \dots

Solution steps

6 x + 9 = x^{2}

Switch sides

x^{2} = 6 x + 9

Move

9

to the left side

x^{2} - 9 = 6 x

Move

6 x

to the left side

x^{2} - 9 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 6 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 9) = 62

x_{1, 2} = \frac{- ( - 6 ) \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 6 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 6 2}{2 \cdot 1} : 3 (1 + 2)

x = \frac{- ( - 6 ) - 6 2}{2 \cdot 1} : 3 (1 - 2)

The solutions to the quadratic equation are:

x = 3 (1 + 2), x = 3 (1 - 2)

- 2 x + 3 < 9

4 (\frac{1}{3})

\frac{\frac{972}{5}}{36}

2.6 - \frac{1}{2}

x^{2} - 36 = 0

What are the solutions to the equation 6x+9=x^2 ?
The solutions to the equation 6x+9=x^2 are x=3(1+sqrt(2)),x=3(1-sqrt(2))
Find the zeros of 6x+9=x^2
The zeros of 6x+9=x^2 are x=3(1+sqrt(2)),x=3(1-sqrt(2))