What is the answer to (2x+1)/3 =(-x+3)/2 ?

The answer to (2x+1)/3 =(-x+3)/2 is x=1

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(2x+1)/3 =(-x+3)/2

\frac{2 x + 1}{3} = \frac{- x + 3}{2}

x = 1

Solution steps

\frac{2 x + 1}{3} = \frac{- x + 3}{2}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(2 x + 1) \cdot 2 = 3 (- x + 3)

Expand

(2 x + 1) \cdot 2 : 4 x + 2

Expand

3 (- x + 3) : - 3 x + 9

4 x + 2 = - 3 x + 9

Move

2

to the right side

4 x = - 3 x + 7

Move

3 x

to the left side

7 x = 7

Divide both sides by

7

x = 1

\frac{x}{5} - \frac{2 x}{3} = \frac{9}{7} - x

y, 4 x + 2 y = 6

x, (x + 4) 2 + (y - 6) 2 = 48

4 + 3 x = 25

y = - (0)^{2}

What is the answer to (2x+1)/3 =(-x+3)/2 ?
The answer to (2x+1)/3 =(-x+3)/2 is x=1
Solve for x: (2x+1)/3 =(-x+3)/2
The solution is x=1