What is the answer to solvefor a,S=ut+1/2 at^2 ?

The answer to solvefor a,S=ut+1/2 at^2 is a=(2S-2ut)/(t^2);\quad t\ne 0

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solvefor a,S=ut+1/2 at^2

solve for

a, S = u t + \frac{1}{2} a t^{2}

a = \frac{2 S - 2 u t}{t ^{2}}; t \neq = 0

Solution steps

S = u t + \frac{1}{2} a t^{2}

Switch sides

u t + \frac{1}{2} a t^{2} = S

Move

u t

to the right side

\frac{1}{2} a t^{2} = S - u t

Multiply both sides by

2

a t^{2} = 2 S - 2 u t

Divide both sides by

t^{2}; t \neq = 0

a = \frac{2 S - 2 u t}{t ^{2}}; t \neq = 0

6 y = - 18

n, d = 4 n - 2

2 (w - 1) + 4 = 4 (w + 1)

\frac{1}{3} (5 x + 4) - \frac{1}{2} (x - 7) = 11

x, m = \frac{x + y}{2}

What is the answer to solvefor a,S=ut+1/2 at^2 ?
The answer to solvefor a,S=ut+1/2 at^2 is a=(2S-2ut)/(t^2);\quad t\ne 0