What is the answer to ((x-1))/3+((2x+1))/5 =((3x-1))/4 ?

The answer to ((x-1))/3+((2x+1))/5 =((3x-1))/4 is x=7

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((x-1))/3+((2x+1))/5 =((3x-1))/4

\frac{( x - 1 )}{3} + \frac{( 2 x + 1 )}{5} = \frac{( 3 x - 1 )}{4}

x = 7

Solution steps

\frac{( x - 1 )}{3} + \frac{( 2 x + 1 )}{5} = \frac{( 3 x - 1 )}{4}

\frac{x - 1}{3} + \frac{2 x + 1}{5} = \frac{( 3 x - 1 )}{4}

Multiply by LCM

20 (x - 1) + 12 (2 x + 1) = 15 (3 x - 1)

Expand

20 (x - 1) + 12 (2 x + 1) : 44 x - 8

Expand

15 (3 x - 1) : 45 x - 15

44 x - 8 = 45 x - 15

Move

8

to the right side

44 x = 45 x - 7

Move

45 x

to the left side

- x = - 7

Divide both sides by

- 1

x = 7

x, y - 5 = 3 (x + 2)

k - 8 = - 8

y, 3 y + \frac{x}{2} - 4 = 8

x, y - 5 = 3 (x - 5)

75 - 5 x = 3 x + 3

What is the answer to ((x-1))/3+((2x+1))/5 =((3x-1))/4 ?
The answer to ((x-1))/3+((2x+1))/5 =((3x-1))/4 is x=7
Solve for x: ((x-1))/3+((2x+1))/5 =((3x-1))/4
The solution is x=7