What is the answer to x-1-((x-2))/2+((x-3))/3 =0 ?

The answer to x-1-((x-2))/2+((x-3))/3 =0 is x= 6/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x-1-((x-2))/2+((x-3))/3 =0

x - 1 - \frac{( x - 2 )}{2} + \frac{( x - 3 )}{3} = 0

x = \frac{6}{5}

Decimal

x = 1.2

Solution steps

x - 1 - \frac{( x - 2 )}{2} + \frac{( x - 3 )}{3} = 0

x - 1 - \frac{x - 2}{2} + \frac{x - 3}{3} = 0

Multiply by LCM

6 x - 6 - 3 (x - 2) + 2 (x - 3) = 0

Expand

6 x - 6 - 3 (x - 2) + 2 (x - 3) : 5 x - 6

5 x - 6 = 0

Move

6

to the right side

5 x = 6

Divide both sides by

5

x = \frac{6}{5}

3 x - 5 = x + 10

y = - 2 + 6

14 = 3 (x - 2) + 5

y = - 3 - 2

x + \frac{1}{2} = \frac{3}{2}

What is the answer to x-1-((x-2))/2+((x-3))/3 =0 ?
The answer to x-1-((x-2))/2+((x-3))/3 =0 is x= 6/5
Solve for x: x-1-((x-2))/2+((x-3))/3 =0
The solution is x= 6/5