What is the answer to (x-13)(x+a)=x^2+13x-13a ?

The answer to (x-13)(x+a)=x^2+13x-13a is x=0

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(x-13)(x+a)=x^2+13x-13a

(x - 13) (x + a) = x^{2} + 13 x - 13 a

x = 0

Solution steps

(x - 13) (x + a) = x^{2} + 13 x - 13 a

Expand

(x - 13) (x + a) : x^{2} + a x - 13 x - 13 a

x^{2} + a x - 13 x - 13 a = x^{2} + 13 x - 13 a

Move

13 a

to the right side

x^{2} + a x - 13 x = x^{2} + 13 x

Subtract

x^{2} + 13 x

from both sides

x^{2} + a x - 13 x - (x^{2} + 13 x) = x^{2} + 13 x - (x^{2} + 13 x)

Simplify

a x - 26 x = 0

Factor

a x - 26 x : x (a - 26)

x (a - 26) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0

5 x - 3 = 3 x + 7

12 - 7 + 4 x = 25

3 (x + 1) = 2 x + 5

- \frac{5}{6} = - \frac{1}{4} - \frac{7}{10} x

3 = x - 2

What is the answer to (x-13)(x+a)=x^2+13x-13a ?
The answer to (x-13)(x+a)=x^2+13x-13a is x=0