What are the solutions to the equation 3x^2-2x=5 ?

The solutions to the equation 3x^2-2x=5 are x= 5/3 ,x=-1

Find the zeros of 3x^2-2x=5

The zeros of 3x^2-2x=5 are x= 5/3 ,x=-1

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3 x^{2} - 2 x = 5

x = \frac{5}{3}, x = - 1

Decimal Notation

x = 1.66666 \dots, x = - 1

Solution steps

3 x^{2} - 2 x = 5

Move

5

to the left side

3 x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 5) = 8

x_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 3}

x = \frac{- ( - 2 ) + 8}{2 \cdot 3} : \frac{5}{3}

x = \frac{- ( - 2 ) - 8}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 1

6 x + 7 \leq 12 x - 11

4 a - 13 = a + 8

- 0.6 (7)^{2} + 4.8 (7)

lo g_{3125} (625) = \frac{4}{5}

a^{3} - 4 a^{2} b - 21 a b^{2}

What are the solutions to the equation 3x^2-2x=5 ?
The solutions to the equation 3x^2-2x=5 are x= 5/3 ,x=-1
Find the zeros of 3x^2-2x=5
The zeros of 3x^2-2x=5 are x= 5/3 ,x=-1