What is expand (2x^2+6x-4)(2x^2-3x) ?

The solution to expand (2x^2+6x-4)(2x^2-3x) is 4x^4+6x^3-26x^2+12x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x^2+6x-4)(2x^2-3x)

expand

(2 x^{2} + 6 x - 4) (2 x^{2} - 3 x)

4 x^{4} + 6 x^{3} - 26 x^{2} + 12 x

Solution steps

(2 x^{2} + 6 x - 4) (2 x^{2} - 3 x)

Distribute parentheses

= 2 x^{2} \cdot 2 x^{2} + 2 x^{2} (- 3 x) + 6 x \cdot 2 x^{2} + 6 x (- 3 x) - 4 \cdot 2 x^{2} - 4 (- 3 x)

Simplify

2 x^{2} \cdot 2 x^{2} + 2 x^{2} (- 3 x) + 6 x \cdot 2 x^{2} + 6 x (- 3 x) - 4 \cdot 2 x^{2} - 4 (- 3 x) : 4 x^{4} + 6 x^{3} - 26 x^{2} + 12 x

= 4 x^{4} + 6 x^{3} - 26 x^{2} + 12 x

81 + 187 + 7

\frac{2}{3} + \frac{1}{4} \cdot \frac{2}{5} - \frac{3}{4} + \frac{5}{2}

- 6 + i^{335} + 8 i^{87} + - 121

tan (x) + cot (x)

\frac{sin ( x )}{cos ^{2} ( x )}

What is expand (2x^2+6x-4)(2x^2-3x) ?
The solution to expand (2x^2+6x-4)(2x^2-3x) is 4x^4+6x^3-26x^2+12x