What is (x^2-3x-28)/(x^2+9x+20) ?

The solution to (x^2-3x-28)/(x^2+9x+20) is (x-7)/(x+5)

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simplify (x^2-3x-28)/(x^2+9x+20)

simplify

\frac{x ^{2} - 3 x - 28}{x ^{2} + 9 x + 20}

\frac{x - 7}{x + 5}

Solution steps

\frac{x ^{2} - 3 x - 28}{x ^{2} + 9 x + 20}

Factor

x^{2} - 3 x - 28 : (x + 4) (x - 7)

= \frac{( x + 4 ) ( x - 7 )}{x ^{2} + 9 x + 20}

Factor

x^{2} + 9 x + 20 : (x + 4) (x + 5)

= \frac{( x + 4 ) ( x - 7 )}{( x + 4 ) ( x + 5 )}

Cancel the common factor:

x + 4

= \frac{x - 7}{x + 5}

\frac{( p ^{2} \cdot q ) ^{3}}{p ^{7} \cdot q ^{2}} \cdot pq

tan^{2} (x) - sec^{2} (x)

(sin (x) - cos (x))^{2}

\frac{2 x ^{3} + 4 x ^{2} + 2 x}{6 x ^{3} - 6 x}

tan (x) cos (x)

What is (x^2-3x-28)/(x^2+9x+20) ?
The solution to (x^2-3x-28)/(x^2+9x+20) is (x-7)/(x+5)