What are the solutions to the equation m^2-6m+8=0 ?

The solutions to the equation m^2-6m+8=0 are m=4,m=2

Find the zeros of m^2-6m+8=0

The zeros of m^2-6m+8=0 are m=4,m=2

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m^{2} - 6 m + 8 = 0

m = 4, m = 2

Solution steps

m^{2} - 6 m + 8 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

m_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, m_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

m = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

m = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

m = 4, m = 2

\frac{12}{4} + 2 \cdot \frac{1}{2} - 3

6 \leq x < 10

x + 9 > 21

- 4 (- 1)

x^{2} - 18 x + 81 = 4

What are the solutions to the equation m^2-6m+8=0 ?
The solutions to the equation m^2-6m+8=0 are m=4,m=2
Find the zeros of m^2-6m+8=0
The zeros of m^2-6m+8=0 are m=4,m=2