What is ((4*3^{22}+7*3^{21})*57)/((19*27^4)^2) ?

The solution to ((4*3^{22}+7*3^{21})*57)/((19*27^4)^2) is (4*3^{22}+7*3^{21})/(19*3^{23)}

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simplify ((43^{22}+73^{21})57)/((1927^4)^2)

simplify

\frac{( 4 \cdot 3 ^{22} + 7 \cdot 3 ^{21} ) \cdot 57}{( 19 \cdot 2 7 ^{4} ) ^{2}}

\frac{4 \cdot 3 ^{22} + 7 \cdot 3 ^{21}}{19 \cdot 3 ^{23}}

Decimal Notation

0.11111 \dots

Solution steps

\frac{( 4 \cdot 3 ^{22} + 7 \cdot 3 ^{21} ) \cdot 57}{( 19 \cdot 2 7 ^{4} ) ^{2}}

(19 \cdot 2 7^{4})^{2} = 1 9^{2} \cdot 2 7^{8}

= \frac{( 4 \cdot 3 ^{22} + 7 \cdot 3 ^{21} ) \cdot 57}{1 9 ^{2} \cdot 2 7 ^{8}}

Factor the number:

57 = 19 \cdot 3

= \frac{( 4 \cdot 3 ^{22} + 7 \cdot 3 ^{21} ) \cdot 19 \cdot 3}{1 9 ^{2} \cdot 2 7 ^{8}}

\frac{19}{1 9 ^{2}} = \frac{1}{19}

= \frac{( 4 \cdot 3 ^{22} + 7 \cdot 3 ^{21} ) \cdot 3}{19 \cdot 2 7 ^{8}}

Factor

2 7^{8} : 3^{24}

= \frac{( 4 \cdot 3 ^{22} + 7 \cdot 3 ^{21} ) \cdot 3}{19 \cdot 3 ^{24}}

\frac{3}{3 ^{24}} = \frac{1}{3 ^{23}}

= \frac{4 \cdot 3 ^{22} + 7 \cdot 3 ^{21}}{19 \cdot 3 ^{23}}

\frac{( x ^{2} y ^{- 3} ) ^{\frac{1}{4}}}{x ^{- 1} y ^{2}}

\frac{cot ( x )}{csc ( x )}

\frac{3 a ^{2} - 3 a - 6}{3 a ^{2} - 3}

(\frac{3 ^{- 1} 2 ^{\frac{1}{4}}}{3 ^{- 2} 2 ^{\frac{1}{2}}})^{- 2}

sin^{2} (θ) + cos^{2} (θ)

What is ((4*3^{22}+7*3^{21})*57)/((19*27^4)^2) ?
The solution to ((4*3^{22}+7*3^{21})*57)/((19*27^4)^2) is (4*3^{22}+7*3^{21})/(19*3^{23)}