What is (7t^2+6t-1)-(3t-5t^2+4-t^3) ?

The solution to (7t^2+6t-1)-(3t-5t^2+4-t^3) is t^3+12t^2+3t-5

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simplify (7t^2+6t-1)-(3t-5t^2+4-t^3)

simplify

(7 t^{2} + 6 t - 1) - (3 t - 5 t^{2} + 4 - t^{3})

t^{3} + 12 t^{2} + 3 t - 5

Solution steps

(7 t^{2} + 6 t - 1) - (3 t - 5 t^{2} + 4 - t^{3})

Apply rule:

(a) = a

(7 t^{2} + 6 t - 1) = 7 t^{2} + 6 t - 1

= 7 t^{2} + 6 t - 1 - (3 t - 5 t^{2} + 4 - t^{3})

Apply the distributive law:

- (a - b) = - a + b

- (3 t - 5 t^{2} + 4 - t^{3}) = - 3 t + 5 t^{2} - 4 + t^{3}

= 7 t^{2} + 6 t - 1 - 3 t + 5 t^{2} - 4 + t^{3}

Group like terms

= t^{3} + 7 t^{2} + 5 t^{2} + 6 t - 3 t - 1 - 4

Add similar elements:

7 t^{2} + 5 t^{2} = 12 t^{2}

= t^{3} + 12 t^{2} + 6 t - 3 t - 1 - 4

Add similar elements:

6 t - 3 t = 3 t

= t^{3} + 12 t^{2} + 3 t - 1 - 4

Subtract the numbers:

- 1 - 4 = - 5

= t^{3} + 12 t^{2} + 3 t - 5

\frac{2 + 4 i}{1 - i} + 2 i (3 - i)

\frac{1 - ( 3 + i ) ^{2} ( 1 - 2 i )}{2 i ^{77} - i ^{726}}

\frac{74}{1.6 5 ^{2}}

x y + 4 x y^{2}

\frac{cos ( x )}{sin ^{2} ( x )}

What is (7t^2+6t-1)-(3t-5t^2+4-t^3) ?
The solution to (7t^2+6t-1)-(3t-5t^2+4-t^3) is t^3+12t^2+3t-5