What is (1/3 a^{2m})^3*(9a^2)^2 ?

The solution to (1/3 a^{2m})^3*(9a^2)^2 is 3a^{6m+4}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (1/3 a^{2m})^3*(9a^2)^2

simplify

(\frac{1}{3} a^{2 m})^{3} \cdot (9 a^{2})^{2}

3 a^{6 m + 4}

Solution steps

(\frac{1}{3} a^{2 m})^{3} (9 a^{2})^{2}

Simplify

(\frac{1}{3} a^{2 m})^{3} : \frac{1}{27} a^{6 m}

= \frac{1}{27} a^{6 m} (9 a^{2})^{2}

Simplify

(9 a^{2})^{2} : 81 a^{4}

= \frac{1}{27} a^{6 m} \cdot 81 a^{4}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

a^{6 m} a^{4} = a^{6 m + 4}

= \frac{1}{27} a^{6 m + 4} \cdot 81

= \frac{1}{27} \cdot 81 a^{6 m + 4}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 81 a ^{6 m + 4}}{27}

Multiply the numbers:

1 \cdot 81 = 81

= \frac{81 a ^{6 m + 4}}{27}

Divide the numbers:

\frac{81}{27} = 3

= 3 a^{6 m + 4}

(\frac{2}{10})^{- 2}

sin (x) cot (x)

(x + 5) (x + 3) - (x + 7) (x + 1)

1 - cos (2 x)

16 x^{8} y^{13} z^{10}

What is (1/3 a^{2m})^3*(9a^2)^2 ?
The solution to (1/3 a^{2m})^3*(9a^2)^2 is 3a^{6m+4}