What is ln((2xe^β)^2)+e^{(β+ln(3x))} ?

The solution to ln((2xe^β)^2)+e^{(β+ln(3x))} is 2(ln(2x)+β)+3e^βx

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simplify ln((2xe^β)^2)+e^{(β+ln(3x))}

simplify

ln ((2 x e^{β})^{2}) + e^{(β + l n (3 x))}

2 (ln (2 x) + β) + 3 e^{β} x

Solution steps

ln ((2 x e^{β})^{2}) + e^{β + l n (3 x)}

ln ((2 x e^{β})^{2}) = ln (2^{2} e^{2 β} x^{2})

e^{β + l n (3 x)} = 3 e^{β} x

= ln (2^{2} e^{2 β} x^{2}) + 3 e^{β} x

ln (2^{2} x^{2} e^{β \cdot 2}) = 2 (ln (2 x) + β)

= 2 (ln (2 x) + β) + 3 e^{β} x

169 - 144

\frac{x ( x + 3 )}{2 x} \cdot \frac{6 ( x + 2 )}{x ^{2} + 5 x + 6}

csc (x) - sin (x)

- x - y + x y + x^{2}

0. 2^{6} \cdot 2 5^{3}

What is ln((2xe^β)^2)+e^{(β+ln(3x))} ?
The solution to ln((2xe^β)^2)+e^{(β+ln(3x))} is 2(ln(2x)+β)+3e^βx