What is ((3/4+7/8))/((2/5-8/9)) ?

The solution to ((3/4+7/8))/((2/5-8/9)) is -585/176

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simplify ((3/4+7/8))/((2/5-8/9))

simplify

\frac{( \frac{3}{4} + \frac{7}{8} )}{( \frac{2}{5} - \frac{8}{9} )}

- \frac{585}{176}

Decimal Notation

- 3.32386 \dots

Solution steps

\frac{\frac{3}{4} + \frac{7}{8}}{\frac{2}{5} - \frac{8}{9}}

\frac{3}{4} + \frac{7}{8} = \frac{13}{8}

= \frac{\frac{13}{8}}{\frac{2}{5} - \frac{8}{9}}

\frac{2}{5} - \frac{8}{9} = - \frac{22}{45}

= \frac{\frac{13}{8}}{- \frac{22}{45}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{13}{8}}{\frac{22}{45}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

\frac{\frac{13}{8}}{\frac{22}{45}} = \frac{13 \cdot 45}{8 \cdot 22}

= - \frac{13 \cdot 45}{8 \cdot 22}

Multiply the numbers:

13 \cdot 45 = 585

= - \frac{585}{8 \cdot 22}

Multiply the numbers:

8 \cdot 22 = 176

= - \frac{585}{176}

\frac{sec ( θ )}{tan ( θ )}

(1 - sin (x)) (1 + sin (x))

\frac{sin ( 2 x )}{1 + cos ( 2 x )}

(2 x - \frac{1}{8 x})^{2}

1 \frac{1}{3} + \frac{3}{4}

What is ((3/4+7/8))/((2/5-8/9)) ?
The solution to ((3/4+7/8))/((2/5-8/9)) is -585/176