What are the solutions to the equation (x-4)(-5x+1)=0 ?

The solutions to the equation (x-4)(-5x+1)=0 are x=4,x= 1/5

Find the zeros of (x-4)(-5x+1)=0

The zeros of (x-4)(-5x+1)=0 are x=4,x= 1/5

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(x - 4) (- 5 x + 1) = 0

x = 4, x = \frac{1}{5}

Decimal Notation

x = 4, x = 0.2

Solution steps

(x - 4) (- 5 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or - 5 x + 1 = 0

Solve

x - 4 = 0 : x = 4

Solve

- 5 x + 1 = 0 : x = \frac{1}{5}

The solutions to the quadratic equation are:

x = 4, x = \frac{1}{5}

0 = x^{2} + 5 x + 6

14 x + 11 \leq - 31

x^{2} - 5 = 20

2 x^{2} - 11 x = 6

\frac{3 + i}{1 - i}

What are the solutions to the equation (x-4)(-5x+1)=0 ?
The solutions to the equation (x-4)(-5x+1)=0 are x=4,x= 1/5
Find the zeros of (x-4)(-5x+1)=0
The zeros of (x-4)(-5x+1)=0 are x=4,x= 1/5