What is (9^2+1)-2^4*sqrt(16)+(12+3*5)-7 ?

The solution to (9^2+1)-2^4*sqrt(16)+(12+3*5)-7 is 38

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simplify (9^2+1)-2^4sqrt(16)+(12+35)-7

simplify

(9^{2} + 1) - 2^{4} \cdot 16 + (12 + 3 \cdot 5) - 7

38

Solution steps

(9^{2} + 1) - 2^{4} 16 + (12 + 3 \cdot 5) - 7

(9^{2} + 1) - 2^{4} 16 + (12 + 3 \cdot 5) - 7 = 9^{2} + 1 - 2^{4} 16 + 12 + 3 \cdot 5 - 7

= 9^{2} + 1 - 2^{4} 16 + 12 + 3 \cdot 5 - 7

Add the numbers:

1 + 12 - 7 = 6

= 9^{2} + 6 - 2^{4} 16 + 3 \cdot 5

9^{2} = 81

2^{4} 16 = 64

3 \cdot 5 = 15

= 81 + 6 - 64 + 15

Add the numbers:

81 + 6 - 64 + 15 = 38

= 38

\frac{( 1 + 2 i ) ( 3 - i )}{( 2 + i )}

3 a + \frac{2}{3} - \frac{6}{7} a - \frac{2}{9}

sec (x) sin (x)

\frac{a ^{2} - b ^{2}}{3 a ^{2} - 3 ab}

\frac{11 + 2}{11 - 2}

What is (9^2+1)-2^4*sqrt(16)+(12+3*5)-7 ?
The solution to (9^2+1)-2^4*sqrt(16)+(12+3*5)-7 is 38