What is ((2x+7)^5+(x+4)^2-7x)/(x+3) ?

The solution to ((2x+7)^5+(x+4)^2-7x)/(x+3) is (32x^5+560x^4+3920x^3+13721x^2+24011x+16823)/(x+3)

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simplify ((2x+7)^5+(x+4)^2-7x)/(x+3)

simplify

\frac{( 2 x + 7 ) ^{5} + ( x + 4 ) ^{2} - 7 x}{x + 3}

\frac{32 x ^{5} + 560 x ^{4} + 3920 x ^{3} + 13721 x ^{2} + 24011 x + 16823}{x + 3}

Solution steps

\frac{( 2 x + 7 ) ^{5} + ( x + 4 ) ^{2} - 7 x}{x + 3}

Expand

(2 x + 7)^{5} + (x + 4)^{2} - 7 x : 32 x^{5} + 560 x^{4} + 3920 x^{3} + 13721 x^{2} + 24011 x + 16823

= \frac{32 x ^{5} + 560 x ^{4} + 3920 x ^{3} + 13721 x ^{2} + 24011 x + 16823}{x + 3}

\frac{sec ( x )}{cos ( x )}

(\frac{1}{3})^{13} \cdot 3^{13}

\frac{30}{14} \div \frac{60}{35}

sec^{2} (x) + tan^{2} (x)

9 x^{2} + 3 x (x - 2)

What is ((2x+7)^5+(x+4)^2-7x)/(x+3) ?
The solution to ((2x+7)^5+(x+4)^2-7x)/(x+3) is (32x^5+560x^4+3920x^3+13721x^2+24011x+16823)/(x+3)