What is (8-i)/(-6+2i) ?

The solution to (8-i)/(-6+2i) is -5/4-1/4 i

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simplify (8-i)/(-6+2i)

simplify

\frac{8 - i}{- 6 + 2 i}

- \frac{5}{4} - \frac{1}{4} i

Solution steps

\frac{8 - i}{- 6 + 2 i}

Multiply by the conjugate

\frac{- 6 - 2 i}{- 6 - 2 i}

= \frac{( 8 - i ) ( - 6 - 2 i )}{( - 6 + 2 i ) ( - 6 - 2 i )}

Simplify

\frac{( 8 - i ) ( - 6 - 2 i )}{( - 6 + 2 i ) ( - 6 - 2 i )} : \frac{- 50 - 10 i}{40}

= \frac{- 50 - 10 i}{40}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{- 50}{40} + \frac{- 10}{40} i

Simplify

\frac{- 50}{40} + \frac{- 10}{40} i : - \frac{5}{4} - \frac{1}{4} i

= - \frac{5}{4} - \frac{1}{4} i

\frac{x ^{8}}{5 x ^{3}}

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lo g_{4} (16 x^{4} y^{3})

(2 x (x^{2} + 1)^{\frac{1}{2}})^{2}