What are the solutions to the equation x(x+4)=-8 ?

The solutions to the equation x(x+4)=-8 are x=-2+2i,x=-2-2i

Find the zeros of x(x+4)=-8

The zeros of x(x+4)=-8 are x=-2+2i,x=-2-2i

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x (x + 4) = - 8

x = - 2 + 2 i, x = - 2 - 2 i

Solution steps

x (x + 4) = - 8

Expand

x (x + 4) : x^{2} + 4 x

x^{2} + 4 x = - 8

Move

8

to the left side

x^{2} + 4 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 8 : 4 i

x_{1, 2} = \frac{- 4 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 i}{2 \cdot 1}

x = \frac{- 4 + 4 i}{2 \cdot 1} : - 2 + 2 i

x = \frac{- 4 - 4 i}{2 \cdot 1} : - 2 - 2 i

The solutions to the quadratic equation are:

x = - 2 + 2 i, x = - 2 - 2 i

\frac{598%}{26%}

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What are the solutions to the equation x(x+4)=-8 ?
The solutions to the equation x(x+4)=-8 are x=-2+2i,x=-2-2i
Find the zeros of x(x+4)=-8
The zeros of x(x+4)=-8 are x=-2+2i,x=-2-2i