What is ln((2xe^b)^2)+e^{(b+ln(3x))} ?

The solution to ln((2xe^b)^2)+e^{(b+ln(3x))} is 2(ln(2x)+b)+3e^bx

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simplify ln((2xe^b)^2)+e^{(b+ln(3x))}

simplify

ln ((2 x e^{b})^{2}) + e^{(b + l n (3 x))}

2 (ln (2 x) + b) + 3 e^{b} x

Solution steps

ln ((2 x e^{b})^{2}) + e^{b + l n (3 x)}

ln ((2 x e^{b})^{2}) = ln (2^{2} e^{2 b} x^{2})

e^{b + l n (3 x)} = 3 e^{b} x

= ln (2^{2} e^{2 b} x^{2}) + 3 e^{b} x

ln (2^{2} x^{2} e^{b \cdot 2}) = 2 (ln (2 x) + b)

= 2 (ln (2 x) + b) + 3 e^{b} x

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\frac{1}{tan ^{2} ( x )}

\frac{( 100 ) ^{- 80} \cdot ( - 100 ) ^{60}}{1000000}

\frac{2}{5 x ^{2} + 5 x} - \frac{4}{3 x + 3}

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What is ln((2xe^b)^2)+e^{(b+ln(3x))} ?
The solution to ln((2xe^b)^2)+e^{(b+ln(3x))} is 2(ln(2x)+b)+3e^bx