What are the solutions to the equation (-12)^2+x^2=13^2 ?

The solutions to the equation (-12)^2+x^2=13^2 are x=5,x=-5

Find the zeros of (-12)^2+x^2=13^2

The zeros of (-12)^2+x^2=13^2 are x=5,x=-5

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(- 12)^{2} + x^{2} = 1 3^{2}

x = 5, x = - 5

Solution steps

(- 12)^{2} + x^{2} = 1 3^{2}

Expand

(- 12)^{2} + x^{2} : 144 + x^{2}

Expand

1 3^{2} : 169

144 + x^{2} = 169

Move

144

to the right side

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

- 2 x \leq 30 + 7 x

5 x + 34 = - 2 (1 - 7 x)

\frac{( 12 - x )}{2.71} = \frac{4}{100}

\frac{y ^{2}}{y ^{3}}

3^{- 4} = \frac{1}{81}

What are the solutions to the equation (-12)^2+x^2=13^2 ?
The solutions to the equation (-12)^2+x^2=13^2 are x=5,x=-5
Find the zeros of (-12)^2+x^2=13^2
The zeros of (-12)^2+x^2=13^2 are x=5,x=-5