What is (sin(t)-cos(t))^2 ?

The solution to (sin(t)-cos(t))^2 is -sin(2t)+1

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simplify (sin(t)-cos(t))^2

simplify

(sin (t) - cos (t))^{2}

- sin (2 t) + 1

Solution steps

(sin (t) - cos (t))^{2}

Expand

(- cos (t) + sin (t))^{2} : cos^{2} (t) - 2 cos (t) sin (t) + sin^{2} (t)

= cos^{2} (t) + sin^{2} (t) - 2 cos (t) sin (t)

Rewrite using trig identities

= - sin (2 t) + 1

\frac{1}{3} (x^{2} + 2)^{\frac{3}{2}}

\frac{3 x ^{2} - 12}{5 x - 10} \cdot \frac{1}{2 x + 4}

- \frac{1}{2} i^{3} (- 9 - 4) - 3 i^{2}

2 \cdot (b^{2} - b + 7) - (b^{2} + b + 8)

- 2 [7 a - (- 7 a + 5 b - 1 + 6 (a - 8 b + 9)) - (4 b - 8)]