What is (\frac{x-3)/(x-4)-(x+2)/(x+1)}{x+3} ?

The solution to (\frac{x-3)/(x-4)-(x+2)/(x+1)}{x+3} is 5/((x-4)(x+1)(x+3))

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simplify (\frac{x-3)/(x-4)-(x+2)/(x+1)}{x+3}

simplify

\frac{\frac{x - 3}{x - 4} - \frac{x + 2}{x + 1}}{x + 3}

\frac{5}{( x - 4 ) ( x + 1 ) ( x + 3 )}

Solution steps

\frac{\frac{x - 3}{x - 4} - \frac{x + 2}{x + 1}}{x + 3}

Join

\frac{x - 3}{x - 4} - \frac{x + 2}{x + 1} : \frac{5}{( x - 4 ) ( x + 1 )}

= \frac{\frac{5}{( x - 4 ) ( x + 1 )}}{x + 3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{5}{( x - 4 ) ( x + 1 ) ( x + 3 )}

1 + tan^{2} (θ)

\frac{53}{16}

15 a^{3} + 10 a^{2} - 18 b - 27 ab

\frac{12}{x + 1} + \frac{1}{x - 4}

\frac{1}{n - 1} + \frac{1}{n - 3} - \frac{n - 1}{n ^{2} - 4 n + 3}

What is (\frac{x-3)/(x-4)-(x+2)/(x+1)}{x+3} ?
The solution to (\frac{x-3)/(x-4)-(x+2)/(x+1)}{x+3} is 5/((x-4)(x+1)(x+3))