What is factor 81x^2-18x+1 ?

The solution to factor 81x^2-18x+1 is (9x-1)^2

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factor 81x^2-18x+1

factor

81 x^{2} - 18 x + 1

(9 x - 1)^{2}

Solution steps

81 x^{2} - 18 x + 1

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

81 x^{2} = (9 x)^{2}

1 = 1^{2}

- 18 x = - 2 \cdot 9 x \cdot 1

= (9 x)^{2} - 2 \cdot 9 x \cdot 1 + 1^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(9 x)^{2} - 2 \cdot 9 x \cdot 1 + 1^{2} = (9 x - 1)^{2}

= (9 x - 1)^{2}

\frac{x}{2} + 4 x = 9

\frac{( 9 x - 1 )}{13} - \frac{( 5 x - 8 )}{4} = x + 6

0.0 6^{2}

4 v^{3} \cdot v u^{2}

75 p^{5} q^{2}