What is (1/z)/(\frac{z-3){3z}} ?

The solution to (1/z)/(\frac{z-3){3z}} is (1*3)/(z-3)

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simplify (1/z)/(\frac{z-3){3z}}

simplify

\frac{\frac{1}{z}}{\frac{z - 3}{3 z}}

\frac{1 \cdot 3}{z - 3}

Solution steps

\frac{\frac{1}{z}}{\frac{z - 3}{3 z}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{1 \cdot 3 z}{z ( z - 3 )}

Cancel the common factor:

z

= \frac{1 \cdot 3}{z - 3}

x^{2} + 15 x + 14

sin (θ) (csc (θ) - sin (θ))

(1 - sin^{2} (x))^{2}

\frac{\frac{x - 5}{6}}{\frac{2 x - 10}{12}}

(7 a^{6} + 12 a)^{2}

What is (1/z)/(\frac{z-3){3z}} ?
The solution to (1/z)/(\frac{z-3){3z}} is (1*3)/(z-3)