What is ((-1/2)y^4)^3*(-16y^2) ?

The solution to ((-1/2)y^4)^3*(-16y^2) is 2y^{14}

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simplify ((-1/2)y^4)^3*(-16y^2)

simplify

((- \frac{1}{2}) y^{4})^{3} \cdot (- 16 y^{2})

2 y^{14}

Solution steps

((- \frac{1}{2}) y^{4})^{3} (- 16 y^{2})

Apply rule:

a (- b) = - ab

((- \frac{1}{2}) y^{4})^{3} (- 16 y^{2}) = - (- \frac{1}{2} y^{4})^{3} \cdot 16 y^{2}

= - (- \frac{1}{2} y^{4})^{3} \cdot 16 y^{2}

= - 16 (- \frac{1}{2} y^{4})^{3} y^{2}

Simplify

(- \frac{1}{2} y^{4})^{3} : - \frac{y ^{12}}{8}

= - 16 (- \frac{y ^{12}}{8}) y^{2}

Apply rule:

- a (- b) = ab

- 16 (- \frac{y ^{12}}{8}) = 16 \cdot \frac{y ^{12}}{8}

= 16 \cdot \frac{y ^{12}}{8} y^{2}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{16 y ^{12} y ^{2}}{8}

Divide the numbers:

\frac{16}{8} = 2

= 2 y^{12} y^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{12} y^{2} = y^{12 + 2}

= 2 y^{12 + 2}

Add the numbers:

12 + 2 = 14

= 2 y^{14}

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What is ((-1/2)y^4)^3*(-16y^2) ?
The solution to ((-1/2)y^4)^3*(-16y^2) is 2y^{14}