What is (4/3-2/6*7/2)/(2/3+5/6) ?

The solution to (4/3-2/6*7/2)/(2/3+5/6) is 1/9

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simplify (4/3-2/6*7/2)/(2/3+5/6)

simplify

\frac{\frac{4}{3} - \frac{2}{6} \cdot \frac{7}{2}}{\frac{2}{3} + \frac{5}{6}}

\frac{1}{9}

Decimal Notation

0.11111 \dots

Solution steps

\frac{\frac{4}{3} - \frac{2}{6} \cdot \frac{7}{2}}{\frac{2}{3} + \frac{5}{6}}

\frac{4}{3} - \frac{2}{6} \cdot \frac{7}{2} = \frac{1}{6}

= \frac{\frac{1}{6}}{\frac{2}{3} + \frac{5}{6}}

\frac{2}{3} + \frac{5}{6} = \frac{3}{2}

= \frac{\frac{1}{6}}{\frac{3}{2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{1 \cdot 2}{6 \cdot 3}

Cancel

\frac{1 \cdot 2}{6 \cdot 3} : \frac{1}{9}

= \frac{1}{9}

\frac{2}{7 + 2}

(2 \frac{1}{5} a^{5 m - \frac{3}{4}})^{4} \cdot (\frac{5}{11} a^{\frac{5}{4}})^{4}

x^{2} - 2 x y + y^{2} - 1

(x - 5)^{2} - (x + 3)^{2} + 16 x

csc^{4} (x) - cot^{4} (x)

What is (4/3-2/6*7/2)/(2/3+5/6) ?
The solution to (4/3-2/6*7/2)/(2/3+5/6) is 1/9