What is factor 4x^4+20x^3+12x^2 ?

The solution to factor 4x^4+20x^3+12x^2 is 4x^2(x^2+5x+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 4x^4+20x^3+12x^2

factor

4 x^{4} + 20 x^{3} + 12 x^{2}

4 x^{2} (x^{2} + 5 x + 3)

Solution steps

4 x^{4} + 20 x^{3} + 12 x^{2}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{3} = x x^{2}

= 4 x^{2} x^{2} + 20 x x^{2} + 12 x^{2}

Rewrite

20

4 \cdot 5

Rewrite

12

4 \cdot 3

= 4 x^{2} x^{2} + 4 \cdot 5 x x^{2} + 4 \cdot 3 x^{2}

Factor out common term

4 x^{2}

= 4 x^{2} (x^{2} + 5 x + 3)

\frac{28}{7}

6 x + 4 (4 - x) = 48

\frac{3 ( x - 5 )}{8} = 4

\frac{\frac{t ^{n} z - t ^{2 n + 1} z ^{2}}{t + t ^{n + 2}} - n t ^{n - 1} z}{t ^{n}}

2 (- 3)^{3} + 6

What is factor 4x^4+20x^3+12x^2 ?
The solution to factor 4x^4+20x^3+12x^2 is 4x^2(x^2+5x+3)