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Popular >

simplify 2^22^3(2/3)^{-2}

Solution

simplify

2^{2} \cdot 2^{3} \cdot (\frac{2}{3})^{- 2}

Solution

72

Solution steps

2^{2} \cdot 2^{3} (\frac{2}{3})^{- 2}

2^{2} \cdot 2^{3} = 32

= 32 (\frac{2}{3})^{- 2}

(\frac{2}{3})^{- 2} = \frac{3 ^{2}}{2 ^{2}}

= 32 \cdot \frac{3 ^{2}}{2 ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ^{2} \cdot 32}{2 ^{2}}

Factor

32 : 2^{5}

= \frac{2 ^{5} \cdot 3 ^{2}}{2 ^{2}}

Cancel

\frac{3 ^{2} \cdot 2 ^{5}}{2 ^{2}} : 2^{3} \cdot 3^{2}

= 2^{3} \cdot 3^{2}

2^{3} = 8

= 3^{2} \cdot 8

3^{2} = 9

= 8 \cdot 9

Multiply the numbers:

8 \cdot 9 = 72

= 72

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Frequently Asked Questions (FAQ)

What is 2^2*2^3*(2/3)^{-2} ?
The solution to 2^2*2^3*(2/3)^{-2} is 72