What is expand (x-4)(x^2+3x-5) ?

The solution to expand (x-4)(x^2+3x-5) is x^3-x^2-17x+20

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expand (x-4)(x^2+3x-5)

expand

(x - 4) (x^{2} + 3 x - 5)

x^{3} - x^{2} - 17 x + 20

Solution steps

(x - 4) (x^{2} + 3 x - 5)

Distribute parentheses

= x x^{2} + x \cdot 3 x + x (- 5) - 4 x^{2} - 4 \cdot 3 x - 4 (- 5)

Simplify

x x^{2} + x \cdot 3 x + x (- 5) - 4 x^{2} - 4 \cdot 3 x - 4 (- 5) : x^{3} - x^{2} - 17 x + 20

= x^{3} - x^{2} - 17 x + 20

\frac{x}{x ^{2} - x - 2} - \frac{x}{x ^{2} + 4 x - 12} - \frac{2}{x ^{2} + 7 x + 6}

\frac{12 b}{6}

1 - 2 sin^{2} (x) + sin^{4} (x)

\frac{1}{4} 4^{44}

27 p^{3} - 8 q^{3}

What is expand (x-4)(x^2+3x-5) ?
The solution to expand (x-4)(x^2+3x-5) is x^3-x^2-17x+20