What is the domain of f(n)=(3+n-2n^2)/(1+n) ?

The domain of f(n)=(3+n-2n^2)/(1+n) is n -1

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domain of f(n)=(3+n-2n^2)/(1+n)

domain

f (n) = \frac{3 + n - 2 n ^{2}}{1 + n}

n < - 1 or n > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

n = - 1

The function domain

n < - 1 or n > - 1

\frac{F}{4 π \cdot ( 7.5 \cdot 1 0 ^{- 3} ) ^{2}}

1.1 a^{3} - 1.1 b^{3}

s (s + 1) (s^{2} + 4 s + 13)

(2 + 3 + 2 - 3)^{2}

∣ 2 - (2) (5) - 16 ∣ - ∣ 7 - 9 + 3 - 12 ∣

What is the domain of f(n)=(3+n-2n^2)/(1+n) ?
The domain of f(n)=(3+n-2n^2)/(1+n) is n<-1\lor n>-1