What is expand (2x-3)(3x^2+2x-1) ?

The solution to expand (2x-3)(3x^2+2x-1) is 6x^3-5x^2-8x+3

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expand (2x-3)(3x^2+2x-1)

expand

(2 x - 3) (3 x^{2} + 2 x - 1)

6 x^{3} - 5 x^{2} - 8 x + 3

Solution steps

(2 x - 3) (3 x^{2} + 2 x - 1)

Distribute parentheses

= 2 x \cdot 3 x^{2} + 2 x \cdot 2 x + 2 x (- 1) - 3 \cdot 3 x^{2} - 3 \cdot 2 x - 3 (- 1)

Simplify

2 x \cdot 3 x^{2} + 2 x \cdot 2 x + 2 x (- 1) - 3 \cdot 3 x^{2} - 3 \cdot 2 x - 3 (- 1) : 6 x^{3} - 5 x^{2} - 8 x + 3

= 6 x^{3} - 5 x^{2} - 8 x + 3

tan^{2} (θ) + 1

\frac{\frac{3}{4} + \frac{7}{8}}{\frac{2}{5} - \frac{8}{9}}

524 + 23 + 46

\frac{sec ^{2} ( θ ) - 1}{sec ^{2} ( θ )}

\frac{2 x ^{\frac{3}{2}}}{( 16 x ^{4} ) ^{\frac{1}{4}}}

What is expand (2x-3)(3x^2+2x-1) ?
The solution to expand (2x-3)(3x^2+2x-1) is 6x^3-5x^2-8x+3